✦ Scholar's Grimoire
High School Completion Guide
✦ Pre-Algebra
Number sense, operations, and the building blocks of algebra
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✦ Integers and Absolute Value Basic

Integers are all whole numbers, including negatives and zero: ...−3, −2, −1, 0, 1, 2, 3...

Absolute value is the distance from zero on the number line. It is always positive (or zero).

|5| = 5    |−5| = 5    |0| = 0

Adding integers: same signs → add the numbers and keep the sign.

Adding integers: different signs → subtract the numbers and keep the sign of the larger absolute value.

Worked Examples
1
(−4) + 7  → Different signs. 7 − 4 = 3. The larger absolute value (7) is positive, so the answer is +3.
2
(−3) + (−5)  → Same signs (both negative). 3 + 5 = 8. Keep the negative sign: −8.
⁋ Order of Operations (PEMDAS) HS Completion

When a math problem has multiple operations, you must solve them in this exact order:

Parentheses → Exponents → Multiply / Divide (left to right) → Add / Subtract (left to right)
Worked Example: 3 + (2 × 4)² ÷ 8
1
Parentheses first: (2 × 4) = 8  →  3 + 8² ÷ 8
2
Exponents: 8² = 64  →  3 + 64 ÷ 8
3
Division: 64 ÷ 8 = 8  →  3 + 8
4
Addition: 3 + 8 = 11
⅓ Fractions, Decimals, and Percentages HS Completion

Converting:

Fraction to decimal: divide numerator by denominator    3/4 = 0.75
Decimal to percent: multiply by 100    0.75 = 75%
Percent to decimal: divide by 100    40% = 0.40

Adding fractions with different denominators requires finding the Least Common Denominator (LCD).

Worked Example: 1/3 + 1/4
1
Find LCD of 3 and 4: LCD = 12
2
Convert: 1/3 = 4/12   and   1/4 = 3/12
3
Add: 4/12 + 3/12 = 7/12
∶ Ratios and Proportions HS Completion

Ratio: a comparison of two quantities. Can be written as 3:4 or 3/4.

Proportion: a statement that two ratios are equal.   3/4 = 6/8

To solve a proportion, use cross-multiplication:

If a/b = c/d, then a × d = b × c
Worked Example: 3/4 = x/20, solve for x
1
Cross-multiply: 3 × 20 = 4 × x
2
60 = 4x
3
Divide both sides by 4: x = 15
= Basic Equations Basic

Solving an equation means finding the value of the variable that makes both sides equal.

The Balance Rule: whatever you do to one side, you must do to the other side.

One-step examples:
x + 7 = 15  → subtract 7 from both sides  → x = 8
4x = 28  → divide both sides by 4  → x = 7
− Negative Numbers Basic

Think of negative numbers as positions to the left of zero on a number line. The further left, the smaller the number.

Rules for multiplying and dividing:

Same signs (+ × +) or (− × −) → Positive
Different signs (+ × −) or (− × +) → Negative
Worked Examples
1
(−3) × (−4) = +12   (same signs = positive)
2
(−6) × 2 = −12   (different signs = negative)
3
(−20) ÷ (−4) = +5   (same signs = positive)
ⁿ Exponents and Scientific Notation HS Completion

Exponent: tells you how many times to multiply the base by itself.

2³ = 2 × 2 × 2 = 8    (base = 2, exponent = 3)
Negative exponent: 2⁻² = 1 / 2² = 1/4

Scientific notation is a shorthand for very large or very small numbers. Move the decimal so there is one non-zero digit to the left, then count the moves as the exponent of 10.

Worked Examples
1
6,200,000 → Move decimal 6 places left → 6.2 × 10↨
2
0.000045 → Move decimal 5 places right → 4.5 × 10⁻⁵

𝚸 Algebra 1
Equations, inequalities, and graphing lines on the coordinate plane
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= Solving One and Two-Step Equations HS Completion

One-step equations require a single inverse operation to isolate the variable.

x + 5 = 12  → subtract 5 → x = 7
3x = 21  → divide by 3 → x = 7

Two-step equations require two operations, working in reverse order of PEMDAS.

Worked Example: 2x + 3 = 11
1
Subtract 3 from both sides: 2x = 8
2
Divide both sides by 2: x = 4
3
Check: 2(4) + 3 = 8 + 3 = 11 ✓
≠ Inequalities HS Completion

Inequalities are solved just like equations, with one critical rule:

When you multiply or divide both sides by a negative number, FLIP the inequality sign.

Symbols: < (less than)   > (greater than)   ≤ (less than or equal)   ≥ (greater than or equal)

Graphing on a number line: Open circle for < and > (does not include that point). Closed circle for ≤ and ≥ (includes that point).

Worked Example: −2x < 8
1
Divide both sides by −2. Since we are dividing by a negative, flip the sign.
2
x > −4
3
Graph: open circle at −4, shade everything to the right.
∕ Linear Equations and Slope HS Completion

Slope describes how steep a line is: the rise (vertical change) over the run (horizontal change).

m = (y₂ − y₁) / (x₂ − x₁)

A positive slope goes up from left to right. A negative slope goes down from left to right.

Worked Example: Find slope between (1, 3) and (3, 7)
1
Label: x₁ = 1, y₁ = 3, x₂ = 3, y₂ = 7
2
m = (7 − 3) / (3 − 1) = 4 / 2 = 2
𝑦 Slope-Intercept Form HS Completion
y = mx + b    where m = slope  and  b = y-intercept

How to graph: Start by plotting the point (0, b) on the y-axis. Then use the slope m = rise/run to find a second point.

Worked Example: Write equation through (1, 3) and (3, 7)
1
Find slope: m = 2 (from previous example)
2
Plug into y = mx + b using point (1, 3): 3 = 2(1) + b
3
Solve: b = 1
4
Equation: y = 2x + 1
− Graphing Lines Basic

To graph a line in slope-intercept form (y = mx + b):

1
Plot the y-intercept (0, b) on the y-axis.
2
Use the slope: from the y-intercept, move up/down by the rise, then left/right by the run. Plot a second point.
3
Draw a line through both points.

x-intercept: set y = 0 and solve for x.

Worked Example: y = 2x + 1
1
y-intercept: b = 1, so plot (0, 1)
2
Slope m = 2 = 2/1: from (0,1), go up 2, right 1. Plot (1, 3).
3
x-intercept: set y = 0 → 0 = 2x + 1 → x = −1/2
≡ Systems of Equations HS Completion

A system of equations is two equations with two variables. The solution is the point (x, y) where both equations are true at the same time.

Substitution method: Solve one equation for one variable, then substitute that expression into the other equation.

Substitution: y = x + 2 and 2x + y = 8
1
Substitute y = x + 2 into the second equation: 2x + (x + 2) = 8
2
3x + 2 = 8 → 3x = 6 → x = 2
3
Plug back in: y = 2 + 2 = 4. Solution: (2, 4)

Elimination method: Add or subtract the two equations to cancel out one variable entirely.

Elimination: x + y = 6 and x − y = 2
1
Add the equations: (x + y) + (x − y) = 6 + 2 → 2x = 8 → x = 4
2
Substitute x = 4 into first equation: 4 + y = 6 → y = 2. Solution: (4, 2)
𝛘 Polynomials Basic

A polynomial is an expression made of terms with variables and exponents. Examples: 3x² + 2x − 5

Adding/Subtracting: Combine like terms (same variable and exponent).

(3x² + 2x) + (x² + 5x − 1) = 4x² + 7x − 1

Multiplying (FOIL method): For two binomials, multiply First, Outer, Inner, Last terms.

Worked Example: (x + 3)(x + 2)
1
First: x × x = x²
2
Outer: x × 2 = 2x
3
Inner: 3 × x = 3x
4
Last: 3 × 2 = 6
5
Combine: x² + 2x + 3x + 6 = x² + 5x + 6
🔐 Factoring Basics HS Completion

Greatest Common Factor (GCF): Always check if you can factor out a GCF first.

6x² + 9x → GCF is 3x → 3x(2x + 3)

Factoring trinomials (ax² + bx + c where a = 1): Find two numbers that multiply to c and add to b.

Worked Example: x² + 5x + 6
1
Need two numbers that multiply to 6 and add to 5.
2
2 × 3 = 6 and 2 + 3 = 5. Those numbers are 2 and 3.
3
Factored form: (x + 2)(x + 3)

𝛋 Algebra 2
Quadratics, functions, exponentials, and sequences
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𝛘² Quadratic Equations HS Completion

Standard form:

ax² + bx + c = 0

The graph of a quadratic is called a parabola. It has a turning point called the vertex. If a > 0, it opens upward; if a < 0, it opens downward.

Solving by factoring is the reverse of FOIL.

Worked Example: x² − 5x + 6 = 0
1
Find two numbers that multiply to 6 and add to −5:   −2 and −3
2
Factor: (x − 2)(x − 3) = 0
3
Set each factor to zero: x − 2 = 0 or x − 3 = 0
4
Solutions: x = 2 or x = 3
±√ The Quadratic Formula HS Completion

When factoring is not obvious, use the quadratic formula to solve any quadratic equation.

x = (−b ± √(b² − 4ac)) / 2a

The Discriminant is b² − 4ac. It tells you how many real solutions exist:

Discriminant > 0 → two real solutions
Discriminant = 0 → one real solution
Discriminant < 0 → no real solutions
Worked Example: 2x² + 3x − 2 = 0   (a=2, b=3, c=−2)
1
Discriminant: b² − 4ac = 9 − 4(2)(−2) = 9 + 16 = 25
2
x = (−3 ± √25) / (2 × 2) = (−3 ± 5) / 4
3
x = (−3 + 5) / 4 = 2/4 = 1/2
4
x = (−3 − 5) / 4 = −8/4 = −2
ƒ Functions and Function Notation HS Completion

A function assigns exactly one output to every input. Think of it as a machine: put in a number, get one number out.

f(x) = 2x + 1 means "plug in x, multiply by 2, then add 1"
f(3) = 2(3) + 1 = 7

Domain: all allowed inputs.   Range: all possible outputs.

Vertical Line Test: a graph represents a function if any vertical line crosses it at most once.

Worked Example: f(x) = x² − 2x + 1, find f(3)
1
Replace every x with 3: f(3) = (3)² − 2(3) + 1
2
= 9 − 6 + 1 = 4
ₑ Exponential Functions HS Completion
f(x) = a · b⁽    where b is the base (b > 0, b ≠ 1)

b > 1: exponential growth (the output gets bigger and bigger fast)

0 < b < 1: exponential decay (the output shrinks toward zero)

Real-world examples: compound interest, population growth, radioactive decay.

Table of values for f(x) = 2⁽
x = −2 → f(−2) = 1/4  |  x = −1 → f(−1) = 1/2
x = 0 → f(0) = 1  |  x = 1 → f(1) = 2
x = 2 → f(2) = 4  |  x = 3 → f(3) = 8
log Logarithms Basics HS Completion

A logarithm is the inverse of an exponent. It asks: "What power do I raise the base to, to get this number?"

If 2³ = 8, then log₂(8) = 3
If b³ = x, then logₒ(x) = n

Common log: log₁₀ written as just "log"    Natural log: ln (base e ≈ 2.718)

Key log rules:

Product: log(AB) = log(A) + log(B)
Quotient: log(A/B) = log(A) − log(B)
Power: log(Aⁿ) = n · log(A)
Worked Example: log₂(32)
1
Ask: "2 to what power equals 32?"
2
2¹ = 32, so log₂(32) = 5
… Sequences and Series Basics HS Completion

Arithmetic sequence: each term is found by adding the same number (common difference d).

Example: 2, 5, 8, 11...   (d = 3)
nth term formula: aₙ = a₁ + (n − 1)d

Geometric sequence: each term is found by multiplying by the same number (common ratio r).

Example: 2, 6, 18, 54...   (r = 3)
nth term formula: aₙ = a₁ · rⁿ⁻¹

Sum of an arithmetic series:

Sₙ = n/2 · (a₁ + aₙ)    (n terms, first term a₁, last term aₙ)
Worked Example: Find the 10th term of 2, 5, 8, 11...
1
a₁ = 2, d = 3, n = 10
2
a₁₀ = 2 + (10 − 1)(3) = 2 + 27 = 29

△ Geometry
Shapes, measurements, and spatial reasoning
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📜 Abbreviation Key
SymbolMeaning
lLength
wWidth
hHeight
bBase
rRadius
dDiameter
sSide
AArea
PPerimeter
VVolume
CCircumference
πPi (approximately 3.14159...)
a, b, cSides of a triangle (c = hypotenuse in right triangles)
∟ Lines and Angles Basic

Angle types:

Acute angle: less than 90°
Right angle: exactly 90°
Obtuse angle: between 90° and 180°
Straight angle: exactly 180°

Angle pairs:

Complementary: two angles that sum to 90°
Supplementary: two angles that sum to 180°
Vertical angles: opposite angles formed by two intersecting lines (always equal)

Transversal crossing parallel lines creates pairs of equal angles:

Alternate interior angles: equal
Corresponding angles: equal
Co-interior (same-side interior) angles: supplementary (sum to 180°)
△ Triangles and Triangle Theorems HS Completion
The sum of interior angles of any triangle = 180°

Types by sides:

Equilateral: all 3 sides equal, all 3 angles = 60°
Isosceles: 2 sides equal, 2 base angles equal
Scalene: no sides equal, no angles equal
Right triangle: one angle = 90°

Triangle Inequality Theorem: the sum of any two sides must be greater than the third side.

a + b > c    b + c > a    a + c > b
√ Pythagorean Theorem HS Completion

In a right triangle, the square of the hypotenuse (c) equals the sum of the squares of the other two sides.

a² + b² = c²    (c is always the hypotenuse, the side opposite the right angle)
Worked Example: Find the hypotenuse if a = 3 and b = 4
1
Write the formula: a² + b² = c²
2
Substitute: 3² + 4² = c² → 9 + 16 = c²
3
25 = c²
4
√25 = c → c = 5
Worked Example: Find missing leg if c = 13 and a = 5
1
5² + b² = 13² → 25 + b² = 169
2
b² = 144 → b = 12
■ Area and Perimeter of All Shapes HS Completion

■ Rectangles and Squares

Rectangle Area: A = l × w
Rectangle Perimeter: P = 2l + 2w
Square Area: A = s²
Square Perimeter: P = 4s

△ Triangles

Triangle Area: A = ½ × b × h
Triangle Perimeter: P = a + b + c

◆ Parallelogram and Trapezoid

Parallelogram Area: A = b × h
Trapezoid Area: A = ½(b₁ + b₂) × h

● Circle

Circle Area: A = πr²
Circumference: C = 2πr = πd
▭ Volume and Surface Area HS Completion

■ Rectangular Prism (Box)

V = l × w × h
SA = 2(lw + lh + wh)
Example: l=5, w=3, h=2
V = 5 × 3 × 2 = 30  |  SA = 2(15 + 10 + 6) = 2(31) = 62

● Cylinder

V = πr²h
SA = 2πr² + 2πrh
Example: r=3, h=5
V = π(9)(5) = 45π ≈ 141.4  |  SA = 2π(9) + 2π(3)(5) = 18π + 30π = 48π ≈ 150.8

▲ Cone and Sphere

Cone Volume: V = ⅓πr²h
Sphere Volume: V = (4/3)πr³
Sphere Surface Area: SA = 4πr²
Example: Sphere with r=3
V = (4/3)π(27) = 36π ≈ 113.1  |  SA = 4π(9) = 36π ≈ 113.1
◯ Circles, Circumference, and Arc Length HS Completion
Circumference: C = 2πr = πd
Area: A = πr²
Arc Length = (angle / 360) × C
Sector Area = (angle / 360) × πr²
Worked Example: Circle with r=6, central angle = 90°
1
Full circumference: C = 2π(6) = 12π
2
Arc length = (90/360) × 12π = (1/4) × 12π = 3π ≈ 9.42
3
Sector area = (90/360) × π(36) = (1/4) × 36π = 9π ≈ 28.3
⚬ Coordinate Geometry HS Completion
Distance: d = √((x₂−x₁)² + (y₂−y₁)²)
Midpoint: M = ((x₁+x₂)/2, (y₁+y₂)/2)
Worked Example: Points A(1, 2) and B(4, 6)
1
Distance: d = √((4−1)² + (6−2)²) = √(9 + 16) = √25 = 5
2
Midpoint: M = ((1+4)/2, (2+6)/2) = (2.5, 4)
↻ Transformations Basic

Translation (slide): Add or subtract from the coordinates.

(x, y) → (x + a, y + b)    shifts right by a and up by b

Reflection (flip):

Reflect over x-axis: (x, y) → (x, −y)
Reflect over y-axis: (x, y) → (−x, y)

Rotation:

90° clockwise: (x, y) → (y, −x)

Dilation (scale): Multiply both coordinates by the scale factor k.

(x, y) → (kx, ky)    k > 1 enlarges, 0 < k < 1 shrinks

⎌ Trigonometry
Right triangles, ratios, and the unit circle
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△ Right Triangle Trigonometry Basic

Trigonometry with right triangles requires identifying three sides relative to the angle you are working with (call it θ):

Hypotenuse: the longest side, always opposite the right angle
Opposite: the side directly across from angle θ
Adjacent: the side next to angle θ (that is not the hypotenuse)

The same triangle has different "opposite" and "adjacent" labels depending on which angle you pick as θ.

SOH CAH TOA HS Completion

The three core trig ratios for a right triangle:

SOH: sin(θ) = Opposite / Hypotenuse
CAH: cos(θ) = Adjacent / Hypotenuse
TOA: tan(θ) = Opposite / Adjacent
Worked Example: Find the missing side

Right triangle, θ = 30°, hypotenuse = 10. Find the side opposite θ.

1
We know the hypotenuse and want the opposite side, so use sin.
2
sin(30°) = opposite / 10
3
sin(30°) = 0.5, so: 0.5 = opposite / 10
4
opposite = 0.5 × 10 = 5
◯ Unit Circle Basics HS Completion

The unit circle is a circle with radius 1 centered at the origin. For any angle θ, the point on the circle is (cos θ, sin θ).

Key angles to memorize:

Anglecos θsin θ
10
30°√3 / 21/2
45°√2 / 2√2 / 2
60°1/2√3 / 2
90°01
~ Sine, Cosine, and Tangent as Functions Basic

When graphed, sine and cosine create smooth wave patterns that repeat. This is called being periodic.

Range of sin and cos: −1 ≤ y ≤ 1
Period of sin and cos: 360° (one full cycle)
Tangent repeats every 180° and has no restricted range

Amplitude: the height of the wave from center to peak. For y = A sin(x), amplitude = |A|.

Period: the horizontal length of one complete cycle. For y = sin(Bx), period = 360° / B.

sin⁻¹ Inverse Trig Functions HS Completion

Inverse trig functions let you find an angle when you know the ratio. They undo the trig function.

arcsin (sin⁻¹): gives the angle whose sine is the input
arccos (cos⁻¹): gives the angle whose cosine is the input
arctan (tan⁻¹): gives the angle whose tangent is the input
Worked Example
1
If sin(θ) = 0.5, what is θ?
2
θ = sin⁻¹(0.5) = 30°
3
If cos(θ) = 0.5, then θ = cos⁻¹(0.5) = 60°
🔄 Trig Applications and Word Problems HS Completion

Angle of elevation: the angle measured upward from horizontal to a line of sight.

Angle of depression: the angle measured downward from horizontal to a line of sight.

The key to word problems is drawing the right triangle and correctly labeling the sides relative to the given angle.

Worked Example: 20-foot ladder at 60°, how high does it reach?
1
The ladder is the hypotenuse (20 ft). The wall height is the side opposite the 60° angle.
2
Use sin: sin(60°) = opposite / hypotenuse = h / 20
3
sin(60°) = √3/2 ≈ 0.866
4
h = 20 × 0.866 = 17.32 feet